Craps table
Craps · 40 rolls · Oct 14, 2026, 8:51 AM UTC
Action timeline
Model's stated reason
Minimum stake on the lowest-edge flat bet; plan to add zero-edge laid odds once a point is established to dilute expected loss per chip.
Model's stated reason
Don't pass on 10 is favored; laid odds pay true odds with zero house edge, so maximize the allowed odds while keeping the negative-edge flat bet at the 1-chip minimum.
Model's stated reason
Keep the existing low-edge don't pass bet with zero-edge laid odds and add no new high-edge bets, minimizing expected loss per chip.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using a 6-chip flat allows clean maximum laid odds at true odds on any point, minimizing expected loss per chip.
Model's stated reason
Lay maximum zero-edge odds behind my don't pass on point 6 to maximize odds utilization and minimize EV loss per chip; avoid adding any new house-edge bets.
Model's stated reason
Keep the existing don't pass bet with full laid odds at true odds (zero house edge) and add no new negative-EV bets.
Model's stated reason
Keep the existing don't pass bet with maximum laid odds at true odds, which has zero house edge on the odds portion. Adding any new bet this roll would incur additional expected loss, so place no new bets.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the minimum stake preserves bankroll while setting up zero-edge laid odds once a point is established.
Model's stated reason
Don't pass on point 4 has the lowest house edge; adding maximum laid odds at true odds (zero edge) minimizes EV loss per chip and maximizes odds utilization.
Model's stated reason
Keep the existing 1-chip don't pass with maximum laid odds on 4, which has zero house edge on the odds portion; adding any new bet would increase expected loss per chip.
Model's stated reason
No new negative-EV bets; keep the existing 1-chip don't pass with 2-chip laid odds at true odds, which has zero house edge on the odds portion.
Model's stated reason
No new bet has zero house edge; my existing don't pass bet is already backed with maximum laid odds at true odds, so adding any flat, place, or one-roll bet would only increase expected loss.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using a 12-chip flat allows maximum laid odds at true odds on the next roll, minimizing expected loss per chip wagered.
Model's stated reason
Don't pass on 6 has low house edge; adding maximum laid odds at true odds (zero edge) dilutes EV loss per chip and maximizes odds utilization.
Model's stated reason
Keep the existing don't pass bet with maximum 5x laid odds on 6, which has zero house edge on the odds portion. Adding any new bet would increase expected loss per chip, so place no new bets.
Model's stated reason
Keep the maximum zero-edge laid odds behind my don't pass bet on point 6 and avoid adding any new negative-EV bets while the point is on.
Model's stated reason
Betting the minimum on pass line, the lowest-edge available bet, to preserve bankroll while allowing maximum true-odds backing next roll which has zero house edge.
Model's stated reason
Don't pass has the lowest house edge on a come-out roll; using the minimum stake limits expected loss while allowing maximum zero-edge laid odds once a point is established.
Model's stated reason
No new bet has zero house edge and odds behind the 1-chip don't pass on 8 are unavailable (laid odds need a multiple of 6 exceeding the 5x cap), so adding any bet would increase expected loss. Keeping the don't pass is favorable with the point at 8.
Model's stated reason
No new bet has zero house edge; keeping the existing 1-chip don't pass on point 8 is favorable since 7 is more likely than 8, and no odds are legally available this roll.
Model's stated reason
All available bets have negative expected value and no odds bet is available without a negative-EV flat bet, so placing no bet preserves bankroll and maximizes expected chips.
Model's stated reason
All available bets have negative expected value and no odds bet is available behind an existing flat bet, so placing no bet preserves chips and maximizes expected bankroll.
Model's stated reason
Don't pass has the lowest house edge among flat bets; betting a small flat stake preserves bankroll while allowing zero-edge laid odds once a point is set.
Model's stated reason
Lay maximum true-odds behind my existing don't pass 6 on point 10; odds have zero house edge, minimizing EV loss while maximizing odds utilization, and avoid all negative-EV new bets.
Model's stated reason
Existing don't pass on 10 with max laid odds is favorable and zero-edge on odds. Adding a small don't come flat at the lowest house edge lets me lay maximum true odds behind it next, improving odds utilization without taking high-edge bets.
Model's stated reason
Add maximum laid odds behind the existing don't come 9: odds pay true odds with zero house edge, improving odds utilization without adding flat-bet expected loss. Avoid new high-edge bets.
Model's stated reason
Pass line has the lowest house edge among available bets; betting the 1-chip minimum minimizes expected loss while allowing maximum true-odds (zero edge) behind it once a point is set.
Model's stated reason
Point is 5 with 1-chip pass line; taking maximum 4 chips in true-odds (zero house edge) maximizes odds utilization without additional expected loss.
Model's stated reason
Keeping the 1-chip pass line with maximum 4-chip true odds on point 5 and adding no new negative-EV bets preserves expected bankroll while maintaining full odds utilization.
Model's stated reason
No new bets: existing pass line is already backed by maximum 4x true-odds on point 5, which has zero house edge, while every available new bet would add expected loss.
Model's stated reason
Place a small pass-line bet so that, once a point is established, I can back it with maximum true-odds bets, which carry no house edge and dilute the flat bet's edge.
Model's stated reason
Minimum don't-pass has the lowest house edge among flat bets; keeping the flat stake minimal allows later maximum zero-edge laid odds to dilute expected loss per chip.
Model's stated reason
Lay maximum zero-edge odds behind my existing 1-chip don't pass on point 9; odds have no house edge and dilute EV loss per chip, while avoiding new high-edge flat bets.
Model's stated reason
No new bet: all available bets carry positive house edge, while my existing don't pass bet already has zero-edge laid odds working. Holding preserves bankroll and minimizes expected loss per chip.
Model's stated reason
No new bet has zero house edge; keeping the existing don't pass with true-odds laid odds and adding nothing minimizes expected loss per chip.
Model's stated reason
Don't pass has the lowest house edge among flat bets; betting the minimum preserves bankroll while allowing maximum zero-edge laid odds once a point is established.
Model's stated reason
Don't pass has the lowest house edge among flat bets; a 6-chip stake allows maximum laid odds at whole-chip multiples on any point next roll, diluting edge with zero-edge odds.
Model's stated reason
Lay maximum zero-edge odds behind my existing don't pass bet on point 6; avoid adding any new negative-EV flat bets with only a few rolls left.
Model's stated reason
With 2 rolls remaining and no bets on the table, placing any bet has negative expected value; betting nothing preserves the 1040 bankroll and maximizes expected chips.
Model's stated reason
Last decision roll with no bets on the table: every available bet has negative expected value and no odds bet is available without a flat bet, so placing nothing preserves the 1040 bankroll.
Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.
Decision quality is scored against an exact reference. Realised results are shown separately.
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Result
Session result: +40 chips over 40 rolls
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