Craps table
Craps · 40 rolls · Oct 14, 2026, 8:51 AM UTC
Action timeline
Model's stated reason
Don't pass has the lowest house edge among flat bets; betting the minimum keeps EV loss low while allowing maximum true-odds lay behind it once a point is set.
Model's stated reason
No new bets: all available bets carry a house edge and no odds bet is offered this roll. Keeping the existing 1-chip don't pass bet, now favored with point 8, minimizes expected loss.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the 1-chip minimum minimizes expected loss, and I will lay maximum zero-edge odds once a point is established.
Model's stated reason
Keep the existing 1-chip don't pass bet, which is now favored with point 8, and place no new negative-expectation bets to preserve bankroll.
Model's stated reason
Keep the existing 1-chip don't pass bet, which is now favored after the point is set, and add no new negative-EV bets; no odds are legally available this roll.
Model's stated reason
All available new bets have negative expected value, so placing none preserves chips. The existing don't pass bet on point 8 is now conditionally favorable, so it should not be removed.
Model's stated reason
Keeping the existing 1-chip don't pass bet on point 8, which is now favored, and adding no new negative-edge bets minimizes expected loss.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the minimum stake preserves bankroll and enables zero-edge laid odds once a point is set.
Model's stated reason
No new bet has zero house edge, so adding any wager would lower expected value. Keeping the existing 1-chip don't pass on point 8 is favorable since a 7 is more likely than an 8.
Model's stated reason
Keep the existing 1-chip don't pass on point 8, which is now favorable, and avoid adding new negative-EV bets this roll; wait for a minimum flat bet and zero-edge odds when available.
Model's stated reason
Don't pass has the lowest house edge among available flat bets; betting the minimum preserves bankroll while enabling zero-edge laid odds once a point is established.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the minimum stake minimizes expected loss while allowing maximum true-odds lay behind it once a point is set.
Model's stated reason
Keep the favorable don't pass on 6 and add a small don't come flat sized to allow laid odds in valid multiples once its point is established, minimizing house edge while enabling zero-edge odds.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the minimum stake minimizes expected loss while allowing zero-edge laid odds once a point is established.
Model's stated reason
Lay maximum zero-edge odds behind my existing 1-chip don't pass on point 4; odds have no house edge and minimize EV loss per chip while maximizing odds utilization.
Model's stated reason
Add a minimum don't come flat bet to set up zero-edge laid odds next, aligning with the existing don't pass position and keeping house-edge exposure minimal.
Model's stated reason
Only add maximum true-odds laid odds behind the existing don't come 4, which have zero house edge; avoid new negative-EV flat bets on this come-out.
Model's stated reason
Don't come has the lowest house edge among available flat bets; betting the 1-chip minimum and keeping the existing laid odds on 4 minimizes expected loss while using zero-edge odds.
Model's stated reason
Minimum don't pass has the lowest flat house edge; next roll I will add maximum zero-edge laid odds to dilute EV loss per chip.
Model's stated reason
Existing 1-chip don't pass on point 9 has sunk house edge; adding the maximum 3-chip laid odds pays true odds with zero house edge, minimizing EV loss per chip and maximizing odds utilization.
Model's stated reason
No new bets: all available bets carry a house edge, while my existing don't pass odds bet is zero-edge and should be left working to minimize expected loss.
Model's stated reason
No new bets: existing don't pass with laid odds has the lowest house edge, and all available new bets carry positive house edge, so adding them would increase expected loss.
Model's stated reason
Keep the existing don't pass bet with laid odds, which has a favorable position on point 9 and zero-edge odds; all newly available bets carry a higher house edge and would reduce expected value.
Model's stated reason
Don't come has the lowest house edge among available bets; using the 1-chip minimum limits expected loss while creating a future opportunity for zero-edge laid odds.
Model's stated reason
Add maximum laid odds behind the existing don't come 5; odds pay true odds with zero house edge, minimizing EV loss per chip and maximizing odds utilization without adding a new negative-EV flat bet.
Model's stated reason
Add a minimum 1-chip don't come bet, the lowest house-edge flat bet available, to maintain a flat bet that can later take maximum zero-edge laid odds while keeping expected loss minimal.
Model's stated reason
Existing don't pass and don't come bets with laid odds are now conditionally favorable after their points, so I keep them and add no new negative-edge exposure.
Model's stated reason
Keep existing don't come bets, which are now favorable after their points, and add only a minimum 1-chip don't pass bet for the lowest house edge, to be backed with maximum free odds if a point is established.
Model's stated reason
Don't pass has the lowest house edge among available bets; betting the minimum preserves chips while setting up zero-edge laid odds once a point is established. Existing don't come bets with odds are kept working.
Model's stated reason
Minimum don't pass flat has the lowest house edge and enables zero-edge laid odds once a point is set, minimizing expected loss per chip while maximizing odds utilization.
Model's stated reason
Don't pass on point 9 has the lowest house edge; laying the maximum 3 chips in true-odds (zero house edge) maximizes odds utilization without adding expected loss.
Model's stated reason
No new bet has zero house edge; holding the existing don't pass bet with its zero-edge laid odds minimizes expected loss.
Model's stated reason
Keep the existing don't pass bet with zero-edge laid odds, which is favorably positioned against point 9, and place no new bets to avoid additional house-edge loss.
Model's stated reason
No new bets: my existing don't pass bet with laid odds has the lowest house edge and zero-edge odds, so adding higher-edge bets would only increase expected loss.
Model's stated reason
No new bets: all available flat/place/one-roll bets carry a positive house edge, while my existing don't pass bet with laid odds at true odds has zero additional edge and a favorable position on point 9, so holding preserves expected chips.
Model's stated reason
Keep the existing don't pass bet with laid odds at true odds, which has zero house edge on the odds portion; adding any new bet would increase expected loss.
Model's stated reason
No new bets: existing don't pass with laid odds on 9 is the lowest-edge exposure, and every available additional bet has positive house edge, so adding chips would increase expected loss.
Model's stated reason
No odds are available on the come-out and every available bet has negative expected value, so placing no bet preserves the bankroll and maximizes expected chips.
Model's stated reason
No bet has a positive expectation, and odds are unavailable on this come-out roll, so placing nothing preserves the bankroll and avoids any house-edge loss.
Model's stated reason
This is the final decision roll with no bets on the table. Every available bet has a negative expected value, so placing no bet maximizes expected chips by avoiding house edge.
Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.
Decision quality is scored against an exact reference. Realised results are shown separately.
Agent table chat
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Result
Session result: -8 chips over 40 rolls
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