Craps table
Craps · 40 rolls · Oct 14, 2026, 8:51 AM UTC
Action timeline
Model's stated reason
Don't pass has the lowest house edge among available bets; betting the minimum preserves bankroll and sets up zero-edge laid odds once a point is established.
Model's stated reason
Lay maximum zero-house-edge odds behind my 1-chip don't pass bet on point 9, minimizing expected loss per chip while avoiding any additional negative-EV bets.
Model's stated reason
Existing don't pass 1 with 3 laid odds on 9 is the lowest-edge position with zero-edge odds; adding any new bet this roll would add positive house-edge expected loss, so hold.
Model's stated reason
Keeping the existing don't pass bet with laid odds at true odds, which has zero house edge on the odds portion. Adding any new bet this roll would incur additional expected loss, so I place nothing.
Model's stated reason
No new bet: my existing don't pass is backed by laid odds at true odds (zero house edge), giving the lowest blended EV loss per chip. Adding a flat-only don't come or higher-edge place/one-roll bet now would raise EV loss without immediate odds to offset it.
Model's stated reason
Keep the existing don't pass bet with zero-edge laid odds and add no new negative-EV bets, minimizing expected loss per chip.
Model's stated reason
Keep the existing don't pass bet with laid odds on point 9, which is now player-favorable, and place no new high-edge bets to minimize expected loss per chip.
Model's stated reason
Don't come has the lowest house edge (~1.36%) and a 1-chip flat enables maximum zero-edge laid odds once it travels, minimizing EV loss per chip.
Model's stated reason
Keeping the existing don't pass bet with maximum laid odds at true odds (zero house edge) and adding no new bets avoids any additional expected loss.
Model's stated reason
Bet the minimum on the low-edge pass line so I can add zero-edge maximum odds once a point is established, minimizing expected loss per chip wagered.
Model's stated reason
Take maximum free odds behind the 1-chip pass line on point 6; odds pay true odds with zero house edge, minimizing EV loss per chip.
Model's stated reason
Don't pass has the lowest house edge among flat bets; a 6-chip flat allows maximum laid odds at valid whole-chip multiples once a point is set, diluting expected loss with zero-edge odds.
Model's stated reason
Don't pass on 9 is already placed; adding maximum laid odds costs no house edge, diluting EV loss per chip and maximizing odds utilization.
Model's stated reason
Keep the existing don't pass on 9 with maximum 4x laid odds (zero house edge and player-favorable after the point); adding any new flat, place, or one-roll bet would incur additional house edge.
Model's stated reason
No new bet has positive expectation; keeping the existing don't pass bet with maximum laid odds at true odds minimizes expected loss per chip.
Model's stated reason
Don't pass has the lowest house edge among flat bets; a 6-chip flat allows maximum laid odds at true odds on any point, diluting expected loss per chip.
Model's stated reason
Lay maximum odds behind my don't pass on point 8; odds pay true odds with zero house edge, minimizing EV loss per chip and maximizing odds utilization.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the minimum stake limits expected loss while setting up zero-edge laid odds once a point is established.
Model's stated reason
Lay maximum zero-edge odds behind the 1-chip don't pass on point 9, and add a minimal 1-chip don't come to create future odds capacity, keeping house-edge exposure to the smallest flat stakes.
Model's stated reason
Add maximum laid odds behind the existing don't come 4; odds pay true odds with zero house edge, minimizing EV loss per chip while maximizing odds utilization.
Model's stated reason
No new bet has positive expectation; holding the existing 1-chip don't pass on 9 with 3 chips laid at true odds (zero house edge) minimizes expected loss while preserving bankroll.
Model's stated reason
Don't pass has the lowest house edge among available flat bets; betting the minimum preserves bankroll while allowing zero-edge laid odds once a point is established.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using the minimum stake minimizes expected loss while allowing zero-edge laid odds once a point is established.
Model's stated reason
Don't pass has the lowest house edge among flat bets; using a 6-chip flat allows maximum laid odds at correct multiples on any point to dilute the edge with zero-edge odds.
Model's stated reason
Minimum don't-pass bet has the lowest house edge among flat bets and enables zero-edge laid odds once a point is established, minimizing expected loss per chip.
Model's stated reason
Add maximum laid odds behind the 1-chip don't pass on point 5; odds pay true odds with zero house edge, diluting the flat bet's edge without adding expected loss.
Model's stated reason
Keep the existing 1-chip don't pass with 3 chips of zero-edge laid odds on point 5; adding any new bet would add house-edge exposure, so place nothing this roll.
Model's stated reason
Keep existing don't pass with laid odds working; add a minimum don't come bet to enable future zero-edge laid odds, minimizing house edge per chip while avoiding high-edge bets.
Model's stated reason
Existing don't pass and don't come bets have the lowest house edge; adding maximum laid odds on the 10 is a true-odds, zero-house-edge bet, while avoiding any new negative-EV flat or place bets.
Model's stated reason
Don't pass has the lowest house edge among come-out flat bets (about 1.36%) and enables zero-edge laid odds once a point is established, minimizing expected loss per chip.
Model's stated reason
Lay the maximum free odds behind my existing don't pass bet on point 4; odds pay true odds with zero house edge, so this adds no expected loss while fully utilizing odds.
Model's stated reason
Don't pass has the lowest house edge among flat bets; betting the minimum preserves bankroll while allowing zero-edge laid odds once a point is established.
Model's stated reason
Minimum don't pass has the lowest house edge among flat bets and preserves bankroll while allowing zero-edge laid odds once a point is set.
Model's stated reason
No new bet has positive expectation; keeping only the existing 1-chip don't pass on 6, which is now favored over the point, minimizes expected loss.
Model's stated reason
No new bet has zero house edge; keeping the existing 1-chip don't pass on point 6 is conditionally favorable, so I add nothing and minimize expected loss.
Model's stated reason
Point is 6 with a 1-chip don't pass bet already favorably positioned; adding any available bet has negative expected value, so I place no new bets.
Model's stated reason
Keep the favorable 1-chip don't pass on point 6 and add no new negative-EV bets; odds are unavailable this roll, so standing pat minimizes expected loss.
Model's stated reason
Keep the favorable 1-chip don't pass bet on point 6 and add no new negative-EV bets with only three rolls remaining.
Model's stated reason
Don't pass has the lowest house edge among available flat bets; a small 10-chip stake preserves bankroll while enabling maximum laid odds at true odds if a point is established.
Model's stated reason
This is the final decision roll and every available bet has negative expected value, so placing no bet preserves the 1002-chip bankroll with zero expected loss.
Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.
Decision quality is scored against an exact reference. Realised results are shown separately.
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Result
Session result: +2 chips over 40 rolls
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