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Craps · 40 rolls · Sep 28, 2026, 9:30 AM UTC

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Action timeline

Model's stated reason

Don't pass has the lowest house edge on the come-out (about 1.36%). A 50-chip flat leaves room within the 300 exposure cap to lay the maximum zero-edge odds once a point is set.

Model's stated reason

The don't pass bet is now favored with the point on 5, so I am keeping it. I am laying the maximum zero-edge odds (99, a multiple of 3) behind it, which maximizes odds utilization without adding any house edge.

Model's stated reason

Keep the don't pass and its laid odds working, since the 5 is set and the laid odds carry zero edge. Add a modest don't come bet so that next roll I can lay full odds behind it with the remaining exposure.

Model's stated reason

Laying the maximum 99 behind my don't come 9 adds a zero-house-edge bet, which lowers my average edge per chip and fills my odds allowance. The existing don't bets are kept because they already hold the advantage after their points were set.

Model's stated reason

The pass line is one of the lowest-edge flat bets. A 50-chip stake leaves 250 of exposure room, enough to take full free odds on any point (up to 5x on 6/8, which fits exactly), which lowers the blended house edge.

Model's stated reason

Free odds carry zero house edge. Taking the maximum allowed 100 chips behind the 50-chip pass line on the 9 lowers the combined edge per chip and maximizes odds utilization.

Model's stated reason

The pass line on 9 already carries the most odds allowed, since the 100-chip per-bet cap sits below the 4x (200) ceiling, and every other available bet has a house edge. The best move is to hold the current low-edge position and add nothing.

Model's stated reason

A come bet carries the low 1.41% edge. Keeping it to 50 leaves 100 chips of exposure room to back it with zero-edge odds once it travels to a point.

Model's stated reason

Free odds carry zero house edge. Putting the full 100 chips of remaining exposure behind the come 6 lowers the overall edge per chip wagered and maximizes odds utilization.

Model's stated reason

The pass line is one of the lowest-edge bets available on the come-out. A 50-chip flat stake leaves room within the 300-chip exposure cap to add up to 5x free odds, which carry no house edge, once a point is set.

Model's stated reason

Free odds carry zero house edge, so I'm taking the maximum allowed 100 behind the pass line on the 5. That minimizes expected loss per chip and maximizes odds utilization.

Model's stated reason

The pass line and its maximum odds on the 5 are set. A modest come bet leaves room to back it with near-full free odds once it travels to a number, which keeps the house edge per chip low while staying under the 300-chip exposure cap.

Model's stated reason

Free odds behind the come 6 carry zero house edge. This uses the 100-chip cap for that bet, which is the most allowed here, and lowers the average edge per chip on the table.

Model's stated reason

Pass line and come bets already carry the maximum 100-chip odds, and exposure is nearly capped. A new flat bet would add house edge and could not get meaningful odds behind it, so I'm standing pat.

Model's stated reason

Both flat bets already carry their maximum allowed odds (100 each, the per-bet cap), and only 20 chips of exposure remain, which is too little to back a new come bet with meaningful odds. Standing pat keeps my average house edge low instead of adding a flat bet at 1.41% with no odds behind it.

Model's stated reason

Both the pass and come bets already carry the maximum 100-chip odds, which have zero house edge. Only 20 chips of exposure remain, so a new flat bet could not be backed with odds and would only add house edge; I'm standing pat.

Model's stated reason

The pass line has one of the lowest house edges available. A 50-chip flat leaves room within the 300 exposure cap to add full free odds (up to 5x on 6/8) once a point is set.

Model's stated reason

Free odds on the point of 8 carry zero house edge. Taking the maximum 100 allowed (a multiple of 5) lowers the average edge per chip and improves odds utilization, while keeping total exposure within the limit.

Model's stated reason

The pass line is already carrying the most odds allowed, since the 100-chip per-bet cap is reached. No new bet here would carry less house edge than what is already on the table, so I stand pat.

Model's stated reason

The pass line and its odds are already at the 100-chip per-bet cap. A modest 30-chip come bet has the lowest-edge flat bet available and leaves 120 chips of exposure room to take near-maximum free odds once it travels to its point.

Model's stated reason

Don't pass has the lowest house edge available on the come-out (1.36%), and it can be backed with laid odds once a point is set, which improves odds utilization; a moderate stake suits the 512 bankroll.

Model's stated reason

Laying the maximum 96 in odds behind the don't pass on 6 adds zero-house-edge action and maximizes odds utilization. The flat don't pass stays up because it is favored now that the point is set.

Model's stated reason

The don't pass on 6 already carries the maximum laid odds, and it is now a favourable position, so I'm keeping it working. I'm adding nothing because every other available bet carries a house edge.

Model's stated reason

The don't pass is already past the come-out with the point on 6, so it now has a positive expected value. The laid odds are at their allowed ceiling, so I'm holding both and adding no new house-edge bets.

Model's stated reason

I'm keeping the don't pass on 6 and its maxed laid odds, since both favour me now that the point is set. I'm adding a small don't come (1.36% edge), sized so zero-edge laid odds can go behind it within the 300-chip exposure cap once it travels to a point.

Model's stated reason

Laying the full 3x odds (60) behind the don't come on 4 adds a zero-house-edge wager, which lowers my average EV loss per chip and maximizes odds utilization while staying within exposure limits. The existing don't pass and its odds stay up, since a don't pass is favored once the point is set.

Model's stated reason

The don't pass on 6 and its laid odds are already at the maximum. A don't pass bet with a point already set is favourable to keep, so I hold. Adding a new flat bet would only add house edge.

Model's stated reason

The don't pass on 6 is now a favourable bet and its laid odds are already at the legal maximum, so I leave both working. I add nothing, because every other bet carries a house edge and would raise the expected loss per chip.

Model's stated reason

The don't pass on 6 already carries the maximum laid odds allowed, and taking it down would give up a favorable position. Any new bet would only add house edge, so I'm standing pat.

Model's stated reason

The don't pass bet and its maxed laid odds on the 6 are now favourable (a 7 comes before a 6 six times out of eleven), so I keep them. I'm adding nothing, because every new bet would carry a house edge.

Model's stated reason

The don't pass is already past the come-out on a point of 6, so it now wins more often than it loses (6/11 vs 5/11), and its laid odds are fair with no house edge; both should stay up. Any new bet would add a house edge with nothing gained in expectation, so I'm standing pat.

Model's stated reason

The don't pass on 6 is already backed by the maximum laid odds, and both bets now favour me, so I keep them working. Adding new bets would only bring more house-edge exposure late in the session.

Model's stated reason

The don't pass on 6 already has the maximum laid odds behind it, and keeping it on the table is favorable once the point is set. Any new bet would only add house edge, so I am standing pat.

Model's stated reason

The don't pass on 6 is already backed with the maximum laid odds, and keeping it is favourable now that the point is set. Adding any new bet would only add house edge, so I'm standing pat.

Model's stated reason

The don't pass on the 6 has a player edge now that the point is set, and the laid odds behind it are zero-edge, so both should stay up. Any new bet would add house edge for no benefit, so I'm standing pat.

Model's stated reason

The don't pass on 6 and its maximum laid odds are already working, and after the point is set that bet favours the player, so I keep both up. I'm adding nothing because every new bet available carries a house edge.

Model's stated reason

The pass line has a low house edge. A 40-chip flat bet leaves bankroll and exposure room to take full zero-edge odds once a point is set, which also helps the odds utilization score.

Model's stated reason

Free odds carry zero house edge, so I'm taking the maximum allowed 100 behind the 8 point. This improves odds utilization without adding any expected loss.

Model's stated reason

Don't pass has the lowest house edge on the menu (1.36%). If a point is set, I can lay zero-edge odds behind it on the final decision roll, which improves both edge and odds utilization.

Model's stated reason

The don't pass on the 8 now has positive expected value, so I'm keeping it up. I'm also laying the maximum 96 in odds behind it, since laid odds carry zero house edge and raise odds utilization without adding expected loss.

Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.

Decision quality is scored against an exact reference. Realised results are shown separately.

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Result

Session result: -700 chips over 40 rolls

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