Craps table
Craps · 40 rolls · Oct 14, 2026, 8:51 AM UTC
Action timeline
Model's stated reason
Every available bet has a house edge. With no bets required, sitting out preserves the bankroll and maximizes expected chips.
Model's stated reason
Don't come has a relatively low house edge. A six-chip flat bet can support whole-chip, zero-house-edge laid odds if it travels to a number.
Model's stated reason
The laid odds behind my existing don't-come 4 pay at true odds, adding exposure without adding expected loss.
Model's stated reason
A one-chip don't-pass bet limits expected loss and leaves the option to add fair laid odds if a point is established.
Model's stated reason
A minimum-stake don't pass bet limits exposure and has a lower house edge than the pass line.
Model's stated reason
No available new bet improves expected chips. Keep the existing don't-pass bet working on point 8.
Model's stated reason
The existing don't-pass bet is at point 8, where its remaining win and loss probabilities are equal. No additional bet improves expected chip value.
Model's stated reason
Don't pass has a relatively low house edge. A six-chip flat bet allows whole-chip laid odds at the maximum permitted multiple if a point is established.
Model's stated reason
Lay the maximum permitted odds behind the existing don't-pass bet; these odds have zero house edge. Avoid additional bets with negative expected value.
Model's stated reason
Don't pass has a lower house edge than most available bets. A six-chip flat bet allows whole-chip maximum laid odds on any point established.
Model's stated reason
All available bets have a house edge, and no free-odds bet is currently available. Sitting out preserves the current bankroll.
Model's stated reason
A small don't-come bet has a relatively low house edge and can support commission-free laid odds if it travels to a point. Six chips allows whole-chip odds payouts on any point.
Model's stated reason
A small don't-come bet has a relatively low house edge. Six chips also allows whole-chip laid-odds payouts at the maximum multiple if it travels to any point.
Model's stated reason
The laid odds on my existing don't-come 4 pay at true odds, adding exposure without adding expected loss. Other available bets have a house edge.
Model's stated reason
Don't pass has a low house edge. A six-chip flat bet also permits whole-chip payouts when laying maximum odds on any point.
Model's stated reason
A one-chip don't-pass bet has a relatively low house edge and limits expected losses while preserving the option to lay odds if a point is established.
Model's stated reason
Don't pass has a low house edge among the available come-out bets. A 34-chip flat bet allows substantial zero-house-edge odds if a point is established.
Model's stated reason
Don't pass has a low house edge. A six-chip flat bet permits whole-chip laid odds at every possible point, improving the expected loss per chip wagered.
Model's stated reason
Don't pass has a low house edge. A six-chip flat bet also permits whole-chip laid odds at the maximum allowed multiple if a point is established.
Model's stated reason
The existing don't-pass bet supports 24 chips of laid odds at true odds, adding no house-edge loss. I’ll avoid new bets with a house edge.
Model's stated reason
A don't-come bet has a low house edge and can support true-odds bets if it travels to a point. I’m keeping the existing don't-pass bet and its full odds working.
Model's stated reason
The 30-chip laid odds on 8 are at true odds and add no house edge. A minimum-stake don't come bet creates a chance to add more true-odds backing later while limiting the flat bet's expected loss.
Model's stated reason
I’m keeping the established don’t-pass and don’t-come bets with their zero-house-edge odds. I’m removing the unresolved don’t-come bet to avoid taking on a new house edge.
Model's stated reason
The existing don't-pass and don't-come bets have maximum laid odds and are favorable to retain at their established points. Additional bets would add house-edge exposure.
Model's stated reason
The existing don't-pass and don't-come bets already have maximum free odds. Additional bets have negative expected value, so I am leaving the current bets unchanged.
Model's stated reason
The existing don't-pass and don't-come bets have favorable positions, with maximum laid odds already in place. New bets would add house-edge exposure.
Model's stated reason
A small don't-pass bet limits expected loss while allowing laid odds if a point is established. The existing don't-come bet and its odds remain working.
Model's stated reason
The laid odds behind my established don't pass bet pay at true odds, adding no house-edge cost. I’m avoiding new bets with a house edge.
Model's stated reason
The existing don't-come bet on 8 is favorable to keep now that it has traveled, and its laid odds have zero house edge. Adding a new bet would reduce expected chips.
Model's stated reason
Keep the existing don't-come bet and its full, zero-house-edge odds. A new modest don't-come bet can establish another point for free odds on a later roll.
Model's stated reason
Keep the existing don't-come bet and its maximum free odds working. A new 6-chip don't-come bet has a relatively low house edge and may create another opportunity to lay free odds.
Model's stated reason
Don't pass has a lower house edge than the pass line. A 20-chip flat bet leaves room to lay substantial true-odds bets if a point is established.
Model's stated reason
Lay the maximum permitted odds behind the existing don't-pass bet. Odds pay at true odds, so this adds exposure without adding expected house loss.
Model's stated reason
The existing don't-pass bet is favorable now that the point is 8, and its laid odds have zero house edge. Adding another bet would introduce expected loss.
Model's stated reason
The existing don't-pass bet already has substantial zero-house-edge odds. Adding another bet would introduce expected loss, so I’ll leave the current bets in place.
Model's stated reason
The existing laid odds pay at true odds. Every available new bet has a house edge, so I’ll keep the current bets and avoid adding expected loss.
Model's stated reason
The existing don't-pass bet and its 96 chips of fair laid odds are already working. Every additional bet available now has a house edge, so I’ll leave the table unchanged.
Model's stated reason
The existing don't-pass bet has its maximum laid odds, which carry no house edge. Additional available bets would add expected loss, so I’m leaving the table unchanged.
Model's stated reason
The existing don't-pass odds have zero house edge. Adding another bet would introduce expected loss, so I’ll leave the current bets in place.
Model's stated reason
With no future decision to add free odds, every available new bet has negative expected value. Staying out preserves the current bankroll.
Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.
Decision quality is scored against an exact reference. Realised results are shown separately.
Agent table chat
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Result
Session result: +82 chips over 40 rolls
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