Blackjack table
Blackjack · 20 rounds · Sep 25, 2026, 8:38 PM UTC
Action timeline
Model's stated reason
With a hard 6 against dealer's 10, hitting is the mathematically optimal play. Standing on 6 leaves me in a very weak position, while hitting gives me a chance to improve without being in immediate bust danger since I can take hits up to 11 without busting.
Model's stated reason
With a hard 10 against dealer's 10, hitting is the correct basic strategy play. A hard 10 has strong potential to improve with any card 7 or higher, while standing gives the dealer a fair chance at 20 or better.
Model's stated reason
With a hard 19 against the dealer's Ace, standing is the mathematically optimal play. A 19 beats most dealer hands, and hitting risks busting with very limited upside since only a 2 would improve the hand to 21.
Model's stated reason
With 15 against dealer's 7, standing is optimal. The dealer has a strong upcard and will likely make 17-21, so hitting 15 risks busting (any card 7+ busts). Basic strategy dictates standing on hard 15 versus dealer 7.
Model's stated reason
With 15 against dealer's 7, standing is optimal. The dealer has a strong upcard showing, but hitting 15 is mathematically unfavorable as most cards worsen the hand; standing gives the dealer the chance to bust.
Model's stated reason
With 12 against dealer's 6, standing is optimal. The dealer has a weak upcard and is likely to bust; hitting 12 risks busting myself with any card 10 or higher while standing lets the dealer's favorable bust probability work in my favor.
Model's stated reason
With 15 against dealer's 4 (weak upcard), standing is optimal. The dealer has a high bust probability (40%+) from this position, and hitting 15 risks busting (54% bust chance) with minimal gain.
Model's stated reason
With a hard 18 against dealer's 7, standing is optimal. This hand wins against most dealer outcomes (bust, 17 or less) and splitting 9s or doubling would be mathematically worse.
Model's stated reason
With 13 against dealer's 2, hitting is optimal as the dealer's weak upcard means they're likely to bust, but my hand is too low to stand. Basic strategy calls for hitting all 13s against 2.
Model's stated reason
With a hard 18 against dealer's 2, standing is the optimal play. The dealer's weak upcard means they're likely to bust, and 18 is a strong hand that wins against most dealer outcomes.
Model's stated reason
With 12 against dealer's Jack (10-value), hitting risks busting with 40% probability. Standing at 12 is the mathematically optimal play against this strong dealer upcard.
Model's stated reason
With a hard 16 against dealer's 10 (likely 10-value card), standing is the statistically correct play. While hit has expected value slightly above stand, the bust risk (37.5%) makes stand the safer choice, especially given that doubling down would risk additional chips with unfavorable odds.
Model's stated reason
I have 20 (K+J), which is a very strong hand. The dealer shows a King (10-value). Standing with 20 is the optimal play—doubling or hitting risks busting or receiving a lower total, while the dealer's 10-value upcard means they likely have at most 20 themselves.
Model's stated reason
With a hard 20 against dealer's 3 (a weak upcard), standing is optimal. This hand wins against most dealer outcomes, and hitting or doubling risks busting or receiving worse cards unnecessarily.
Model's stated reason
With a hard 10 against dealer's 10 upcard, doubling is the mathematically optimal play. A hard 10 doubles against all dealer upcards, and while the dealer shows strength, hitting a 10 still gives excellent odds of improvement to 17-21 on the next card.
Model's stated reason
With 9 against dealer's 6 (a bust card), doubling down is optimal. The dealer has a high probability of busting, and doubling maximizes expected value in this favorable situation.
Model's stated reason
With a hard 11 against dealer's 10 (Queen), doubling down is the optimal play. A hard 11 has high potential to improve to a strong hand (20-21 with a 9 or 10), and doubling maximizes value against the dealer's strong upcard.
Model's stated reason
With 12 against dealer's Ace, hitting is dangerous due to bust risk (16+ out of 13 remaining values in a 52-card deck would bust). Standing gives the best expected value as the dealer must stand on soft 17+ or bust on 4-6, and an Ace likely makes 17+ for the dealer, making aggressive play unfavorable.
Model's stated reason
Player holds 20 (T+J) against dealer's 3, which is an excellent hand. Standing is the correct play as 20 is very strong and doubling risks busting or receiving a low card, while the dealer's weak upcard (3) makes this position favorable.
Model's stated reason
With a pair of deuces against a Queen (10-value card), splitting gives me two chances to build strong hands. The dealer's strong upcard (10-value) makes this a favorable spot to increase my action with a split, since I'm starting from a weak position (total of 4).
Model's stated reason
With a hard 6 against dealer's Queen (10-value), hitting is the mathematically correct play. The dealer is in a strong position, and I need to improve my hand significantly. Standing on 6 would be a weak strategy against this upcard.
Model's stated reason
I have a soft 17 (Ace-2-4) against dealer's Queen (10-value card). Basic strategy recommends standing on soft 17 versus a dealer 10, as hitting risks busting or creating a worse hand, while the dealer likely has 17-20.
Model's stated reason
With 11 against dealer's Queen (10-value), doubling is mathematically optimal as it maximizes expected value against a strong dealer upcard. This is a textbook doubling situation in blackjack.
Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.
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Result
Session result: +5 chips over 20 rounds
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