Craps table
Craps · 40 rolls · Sep 28, 2026, 9:30 AM UTC
Action timeline
Model's stated reason
Don't pass has the lowest house edge on the come-out at 1.36%. A 50-chip flat bet leaves room under the 300 exposure cap to lay zero-edge odds once a point is set.
Model's stated reason
The don't pass bet on 9 is now a favourable bet, so it stays up. I'm laying the maximum 99 chips of zero-edge odds behind it (a multiple of 3) to lower the average house edge per chip and use the full odds allowance.
Model's stated reason
The pass line has one of the lowest house edges available on the come-out, at about 1.41%. A 50-chip flat bet leaves room under the 300 exposure cap to add full zero-edge odds once a point is set.
Model's stated reason
Free odds carry zero house edge, so I'm taking the maximum allowed 100 behind the pass line on the 8. That fully uses the odds allowance and lowers the average edge per chip wagered.
Model's stated reason
Don't pass has the lowest house edge available on the come-out (1.36%). A 50-chip flat keeps room under the 300 exposure cap to lay full zero-edge odds once a point is set.
Model's stated reason
Keep the don't pass: once the point is 6 it is favourable to leave it up. Lay the maximum 96 in odds, which carry no house edge and pay 5:6, so they lower my expected loss per chip and use the full odds allowance.
Model's stated reason
The pass line has one of the lowest house edges at about 1.41%. A 50-chip flat bet leaves room under the 300-chip exposure cap to take full free odds (up to 5x on 6 or 8) once a point is set.
Model's stated reason
Pass odds carry zero house edge, so I'm taking the maximum legal 100 behind the 50 pass line on the 5. That is an even multiple of 2 and within the odds ceiling, which lowers the per-chip edge and maximizes odds utilization.
Model's stated reason
Don't pass has the lowest house edge of any flat bet here. A 50-chip flat bet leaves room under the 300 exposure cap to lay near-maximum free odds once a point is set.
Model's stated reason
The don't pass on point 4 is now a favourable bet, so I am keeping it. I am laying the maximum 100 chips of zero-edge odds behind it, which improves odds utilisation without adding any house edge.
Model's stated reason
The don't pass on point 4 is now strongly favoured, since a 7 is twice as likely as a 4, and the laid odds carry no house edge, so both bets stay up. Adding any new bet would bring back a house edge, so I am making no additions.
Model's stated reason
Keep the don't pass and its full laid odds on the 4, since that position is now favorable. Add a modest don't come bet, which has a low house edge, and keep exposure room to lay zero-edge odds behind it once it travels to a point.
Model's stated reason
Laying the maximum 99 in odds behind the don't come on 5 adds zero-house-edge action, which lowers the average EV loss per chip and maximizes odds utilization within the 120-chip exposure headroom. The don't pass and don't come flat bets are kept because they are favorable to hold once their points are set.
Model's stated reason
Both don't bets are already established on points where they are favoured, and their laid odds sit at the exposure limit. A new don't come flat with the remaining 21 chips would add house edge without enough room left to back it with odds, so I stand pat.
Model's stated reason
The existing don't pass and don't come bets already have points, so they favour me now and should stay up. With only 21 chips of exposure left, I can't add odds behind a new flat bet, so a new wager would only add house edge.
Model's stated reason
My don't pass on 4 and don't come on 5 are established and already carry full laid odds, so they are favorable to keep. The remaining 21 chips of exposure could not take odds, and any new bet would only add house edge, so I am standing pat.
Model's stated reason
The don't pass on 4 and don't come on 5 already have their points set, so they are now favorable to hold, and the laid odds behind them carry no house edge. Exposure is nearly maxed, so I add nothing, since any new bet would carry a house edge without room for odds.
Model's stated reason
The don't pass on 4 and the don't come on 5 already carry the maximum laid odds, and both now have positive expected value, so taking them down would be a mistake. The 21 chips of exposure left are too few to back a new flat bet with full odds, so I hold.
Model's stated reason
The don't pass on 4 and the don't come on 5 are both established and now favor me, and both carry maximum laid odds, so taking anything down would give up value. The 21 chips of remaining exposure could not carry odds, so a new flat bet would only add house edge.
Model's stated reason
The pass line is one of the lowest-edge flat bets, at 1.41%. A 50-chip stake leaves room under the 300 exposure cap to take full zero-edge odds once a point is set.
Model's stated reason
Free odds on the point of 9 carry zero house edge, so I am taking the maximum legal 100 (the per-bet cap, and a multiple of 2) to improve odds utilization and lower edge per chip. I am skipping every other bet because each one adds positive expected loss.
Model's stated reason
The pass line is one of the lowest-edge flat bets. A 50-chip flat leaves room under the 300 exposure cap to take full free odds (up to 5x) once a point is set, which lowers the combined house edge.
Model's stated reason
Adding the maximum 100 chips of zero-edge odds behind the pass line on the 6 lowers the average house edge per chip. It also maximizes odds utilization, and the stake is a multiple of 5 so the 6:5 payout comes out in whole chips.
Model's stated reason
The pass line is one of the lowest-edge bets available on the come-out, at about 1.41%. A 50-chip flat bet leaves room to add up to 250 in zero-edge odds after a point is set without passing the 300 exposure cap.
Model's stated reason
Taking the maximum 100 in free odds behind the pass line on the 9 adds a bet with zero house edge, which lowers my overall expected loss per chip. It pays true odds of 3:2 in even chips.
Model's stated reason
The pass line on 9 already carries the maximum 100-chip odds bet, the lowest-edge setup available. Adding any other bet would only raise the house edge per chip, so I'm holding.
Model's stated reason
The pass line has one of the lowest house edges on the menu (about 1.41%). A 50-chip flat bet leaves room under the 300 exposure cap to add full free odds once a point is set.
Model's stated reason
Pass odds carry zero house edge. Taking the full allowed 100 behind the pass line on the 10 improves odds utilization without adding expected loss.
Model's stated reason
Pass odds are already at the 100-chip per-bet cap, so a 50-chip come bet (1.41% edge) is the lowest-edge way to add action. It leaves exactly 100 chips of exposure for zero-edge odds once it travels to a point.
Model's stated reason
The pass line and full odds on the 10 are already at the per-bet cap, so no more odds can be added. Every other bet carries a house edge, so standing pat keeps expected loss per chip at its minimum.
Model's stated reason
The pass odds are already at the 100-chip per-bet cap. A modest 25-chip come bet (1.41% edge) leaves exposure room to back it with odds once it travels to a point, keeping the blended house edge low.
Model's stated reason
The pass line and 100 in odds on the 10 are already at the 100-chip per-bet cap, so no more zero-edge odds can go on. Any new bet would carry a house edge and raise the expected loss per chip, so I'm standing pat.
Model's stated reason
The pass line and full 100-chip odds are already working on the 10. Adding any other bet would only add house-edge exposure, so I'm holding.
Model's stated reason
A come bet has the lowest house edge still available. It leaves room within the exposure cap to lay free odds behind the come point next roll, which improves odds utilization at zero added edge.
Model's stated reason
Don't pass has the lowest house edge among the available come-out flat bets (about 1.36%). I'm keeping the flat bet moderate so there is room under the 300 exposure cap to lay zero-edge odds once a point is set.
Model's stated reason
Laying the maximum 96 in odds behind the don't pass on 6 adds zero-house-edge exposure and maximizes odds utilization. I'm keeping the don't pass, which is now favorable with the point established.
Model's stated reason
The don't pass on 6 and its laid odds are already at the maximum and favorable once the point is set, so I'm keeping them working. With few rolls left, adding new edge-bearing flat bets would only raise my expected loss per chip.
Model's stated reason
The don't pass on 6 is already backed by maximum laid odds, and with the point set it holds a player edge, so I keep it working. Adding new flat bets with a house edge would only raise expected loss this late in the session.
Model's stated reason
The don't pass on the 6, with laid odds behind it, is already set up and now favors me, so I keep it working and take nothing down. Any new bet would carry a house edge, so I add none.
Model's stated reason
The don't pass on 6 now has positive expected value and its laid odds are already at the maximum, so both stay up. Every new bet carries a house edge, so I place nothing on the final decision roll.
Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.
Decision quality is scored against an exact reference. Realised results are shown separately.
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Result
Session result: +95 chips over 40 rolls
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