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Roulette table

Roulette · 20 spins · Sep 28, 2026, 9:30 AM UTC

10 of 20 decisions were server fallbacks

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Action timeline

Model's stated reason

Bold-play heuristic: a 15-unit straight-up bet pays 525 if it hits, jumping bankroll from 1000 to 1525 (above the 1500 target) in a single spin, while risking only 15 chips if it misses, preserving capital for the remaining 19 spins.

Model's stated reason

With 18 spins left and a 515-chip deficit, I'm using two non-overlapping dozens (63% win probability) to grind the bankroll upward with lower variance than straight-up bets, saving high-variance plays for later if I fall behind pace.

Model's stated reason

Given the large gap to the 1500 target and limited spins remaining, a bold-play approach favors high-payout straight-up bets; splitting the max allowed 200 total stake across two numbers doubles the hit probability while preserving the 35:1 payout needed to jump toward the goal quickly.

Model's stated reason

Need to jump from 585 to 1500 within 16 spins; only a high-payout straight-up bet can deliver the required 915+ profit within the 200-chip spin cap. Spreading 31 chips across six numbers (186 total) maximizes the chance (~15.8%) that a single spin's win pushes bankroll past the target while still respecting per-bet and per-spin stake limits.

Model's stated reason

With 399 chips and 12 spins to reach 1500, spreading modest stakes across five straight-up numbers maximizes per-spin hit probability (5/38) while each win (net ~1116) alone crosses the 1500 target, balancing risk versus reward under the 200-chip spin cap.

Model's stated reason

With only 219 chips and 11 spins left, the bold-play optimal strategy is to bet the minimal straight-up stake (~37) needed so that a win alone pushes bankroll past 1500, preserving remaining chips for future attempts if it misses.

Model's stated reason

With 182 chips and 9 spins left, bold-play theory says to bet the minimum stake on a single high-payout straight-up number that, if it hits, pushes bankroll past 1500 (182+35*38=1512), preserving the rest of the bankroll for future attempts if it misses.

Model's stated reason

With only 6 spins left and a 144-chip bankroll needing to reach 1500, the mathematically optimal 'bold play' approach is to stake just enough on a single straight-up number (39 chips) so that a win (35:1) pushes the bankroll past the 1500 target while preserving the remaining 105 chips as a reserve for subsequent spins if this bet loses.

Model's stated reason

With only 5 spins left and a 105-chip bankroll needing to reach 1500, the sub-fair game favors bold play: place the minimum straight-up stake (40) that, if it hits at 35:1, pushes the bankroll to \u22651500 in a single spin, preserving the remaining 65 chips for subsequent attempts if it misses.

Model's stated reason

Only a 35:1 straight-up bet can turn 65 chips into 1500+ in the final spin; all other bet types have insufficient payout multiples to reach the target.

Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.

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Result

Session result: -1,000 chips over 20 spins

Target reached: no · final bankroll 0 · target 1,500

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