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Craps · 40 rolls · Oct 14, 2026, 8:51 AM UTC

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Action timeline

Model's stated reason

Don't pass has the lowest house edge among flat bets; using the minimum stake preserves bankroll while allowing maximum true-odds bets once a point is set.

Model's stated reason

Take maximum laid odds behind the existing 1-chip don't pass bet on point 10; odds pay true odds with zero house edge, minimizing expected loss per chip.

Model's stated reason

No new bet has positive expectation; keeping only the existing 1-chip don't pass with zero-edge laid odds minimizes expected loss per chip.

Model's stated reason

Don't pass has the lowest house edge among flat bets; using a 6-chip flat allows full laid odds in valid multiples on any point, diluting EV loss with zero-edge odds.

Model's stated reason

Don't pass has the lowest house edge among available flat bets; a small 6-chip stake enables perfectly sized maximum laid odds (with whole-chip payouts) once a point is established, minimizing expected loss.

Model's stated reason

Add maximum laid odds behind the existing don't pass bet on point 8; odds pay true odds with zero house edge, minimizing EV loss per chip and maximizing odds utilization without adding new flat exposure.

Model's stated reason

Keep the existing don't pass bet with maximum laid odds at true odds, which has zero house edge; adding any new flat, place, or one-roll bet would only add negative expected value.

Model's stated reason

Don't pass has the lowest house edge among available bets; using the minimum stake limits expected loss while establishing a flat bet eligible for zero-edge odds once a point is set.

Model's stated reason

Lay maximum odds behind my 1-chip don't pass on point 5; odds pay true odds with zero house edge, minimizing EV loss per chip and maximizing odds utilization.

Model's stated reason

Minimum pass line bet keeps house-edge exposure minimal while enabling zero-edge odds once a point is established.

Model's stated reason

Don't pass has the lowest house edge among flat bets; betting a modest 10 chips enables maximum laid odds at true odds on the next roll, diluting expected loss per chip.

Model's stated reason

Point is 8 with a 10-chip don't pass bet; laying the maximum 48 in odds (multiple of 6) is a zero-house-edge bet that maximizes odds utilization and dilutes EV loss per chip, with no new negative-EV flat bets.

Model's stated reason

No new bet has zero house edge; keeping the existing don't pass bet with near-maximum laid odds at true odds preserves expected value better than adding any negative-EV wager.

Model's stated reason

Keep the existing don't pass bet on 8 with near-max laid odds, which is favorable after the point and has zero house edge on the odds; adding any new flat or place bet now would incur fresh house edge, so place nothing.

Model's stated reason

Place a minimum pass-line bet to keep expected loss minimal while enabling zero-edge odds once a point is established.

Model's stated reason

Don't pass has the lowest house edge among flat bets; betting the minimum preserves bankroll and allows zero-edge laid odds once a point is established.

Model's stated reason

Minimum pass line bet keeps house-edge exposure minimal while enabling zero-edge odds once a point is established.

Model's stated reason

Minimum don't pass has the lowest house edge among flat bets; once a point is set I can add zero-edge laid odds to dilute EV loss per chip.

Model's stated reason

Don't pass has the lowest house edge among available flat bets; betting the minimum preserves chips and enables zero-edge laid odds once a point is established.

Model's stated reason

Don't pass point is 9; adding maximum laid odds (3 chips, multiple of 3) gives zero house-edge exposure and maximizes odds utilization behind the minimal 1-chip flat bet.

Model's stated reason

Keep the existing don't pass bet with zero-edge laid odds and add no new negative-expectation bets, preserving expected bankroll.

Model's stated reason

Point is 9 with don't pass 1 and maximum laid odds 3 already working at zero house edge. Adding any new bet now would add house-edge cost, so I hold and wait for the next come-out to place a minimum flat bet with maximum odds.

Model's stated reason

Don't come has the lowest house edge among available bets (~1.36%); a 1-chip flat bet minimizes expected loss while allowing zero-edge laid odds on a later roll.

Model's stated reason

Add maximum laid odds behind the don't come 5: odds pay true odds with zero house edge, improving odds utilization without adding expected loss from new flat or high-edge bets.

Model's stated reason

Don't come has one of the lowest house edges; a minimum 1-chip flat keeps expected loss tiny and creates a point for maximum zero-edge laid odds next roll.

Model's stated reason

Add maximum laid odds behind the don't come 5: odds pay true odds with zero house edge, minimizing EV loss while increasing odds utilization. Avoid new flat or high-edge bets.

Model's stated reason

Keep the existing don't-come bet with zero-edge laid odds and place no new negative-EV bets on this come-out roll to preserve bankroll.

Model's stated reason

No new bet has positive expectation; keeping the existing don't-come bet with its zero-edge laid odds and avoiding high-edge one-roll or place bets preserves expected chips.

Model's stated reason

Don't pass has the lowest house edge on a come-out roll; betting the minimum keeps EV loss low while preserving bankroll to add zero-edge laid odds once a point is established.

Model's stated reason

No new bet has positive expectation; keeping the existing low-edge don't pass and don't come bets with laid odds, which are favorably positioned against their points, maximizes expected chips.

Model's stated reason

Don't come has the lowest house edge among legal new bets (~1.36%); adding a 1-chip bet preserves low per-chip EV loss while existing don't pass/don't come odds remain at true odds.

Model's stated reason

Minimum-stake don't pass has the lowest house edge among available flat bets (about 1.36%); once a point is set I can add zero-edge laid odds to dilute EV loss per chip.

Model's stated reason

All available bets have negative expected value and no odds bet is offered this roll, so placing nothing preserves chips while the existing 1-chip don't pass bet resolves.

Model's stated reason

No new bet has zero house edge; keeping only the existing 1-chip don't pass minimizes expected loss, and no odds bet is legal this roll.

Model's stated reason

No new bet has positive expectation; all available bets carry a house edge. Keeping the existing 1-chip don't pass on point 8, which is now favored to win on a 7 before 8, and adding nothing minimizes expected loss.

Model's stated reason

No new bet has zero or positive expectation; keeping only the existing 1-chip don't pass on 8, which is now favored, preserves bankroll and avoids additional house edge.

Model's stated reason

No new bet has zero house edge; all available bets have negative expectation. Keeping the existing 1-chip don't pass bet, which is now favored on point 8, and adding nothing maximizes expected chips.

Model's stated reason

Keep the existing 1-chip don't pass bet on point 8 and add no new negative-expectation bets; no odds bet is offered among this roll's legal bet ids.

Model's stated reason

No new bets: all available bets carry a positive house edge and no odds bet is offered this roll, so preserving bankroll maximizes expected chips. Keeping the existing 1-chip don't pass on point 8 is favorable since 7 is more likely than 8.

Model's stated reason

No bet has positive expected value, and on this final come-out roll no zero-edge odds can be added yet, so placing no bet preserves the 1020 bankroll and minimizes expected loss.

Stated reasons appear after the comparison block is revealed. They are model-submitted text, not verified reasoning.

Decision quality is scored against an exact reference. Realised results are shown separately.

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Result

Session result: +20 chips over 40 rolls

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